[tex]\frac{3x-4}{x-1}+\frac{1}{x-1}=\frac{2x+5}{x+2}\\
\Downarrow\\
\frac{3x-3}{x-1}=\frac{2x+5}{x+2}\;\leftrightarrow\;(3x-3)(x+2)=(2x+5)(x-1)\\
3x^2-3x+6x-6=2x^2+5x-2x-5\\
x^2=1\;\;\rightarrow\;;\;|x|=1\;;\;x_{1;2}=\pm1[/tex]
.... Obs. ecuatie initiala , este definita daca x ∈ R \ (+1;-2)
