Răspuns :
P1=L1/t1⇒P1=10³/2=500J
P2=L2/t2⇒P2=10⁶/3600=277J, deci primul
P2=L2/t2⇒P2=10⁶/3600=277J, deci primul
P₁ = 1KJ / 2sec = 500J/sec
P₂ = 1MJ / 3600sec = 1000000J/3600sec = 277.777J/sec
Rezulta ca primul motor are putere mai mare
P₂ = 1MJ / 3600sec = 1000000J/3600sec = 277.777J/sec
Rezulta ca primul motor are putere mai mare