👤
Lupusebi
a fost răspuns

a)(2x+3)² >2x(2x+5)+1
b)x(x+1)-6≥(x-2)²
c)x(4x+5)<(2x-1)²+8
d)(x+3)²<(x-1)²+24
 ????

Răspuns :

Cristinatibulca
4x²+12x+9>4x²+10x+1
2x>-8, x>-4, x∈(-4, +infinit)

x²+x-6≥x²-4x+4
5x≥10, x≥2, x∈[2, +infinit)

4x²+5x<4x²-4x+1+8
9x<9, x<1, x∈(-infinit, 1)

x²+6x+9<x²-2x+1+24
8x<16, x<2, x∈(- infint, 2)

Alte intrebari