a) x
x+1
x+2
[tex] \frac{a+b+c}{3}=90 [/tex]
[tex] \frac{x+x+1+x+2}{3}=90 [/tex]
[tex] \frac{3x+3}{3}=90=\ \textgreater \ 3x+3=3*90[/tex]
3x+3=270 |-3
3x=267
x=267:3
x=89
Nr. sunt:89,90,91
b)x
x+1
x+2
[tex] \frac{x+x+1+x+2}{3}=105[/tex]
[tex] \frac{3x+3}{3}=105=\ \textgreater \ 3x+3=3*105 [/tex]
3x+3=315
3x=315-3
3x=312
x=104
Nr.sunt:104,105,106
c)x
x+1
x+2
[tex] \frac{x+x+1+x+2}{3}=2002[/tex][tex] \frac{3x+3}{3}=2002 [/tex]
3x+3=3*2002
3x+3=6006 |-3
3x=6003
x=6003:3
x=2001
Nr. sunt 2001,2002,2003
