Salut!
Ai mai jos rezolvarea in limbaj C++
#include <iostream>
using namespace std;
int v[11];
int clean()
{
for (int i = 0; i < 10; i++)
v[i] = 0;
}
int verifica()
{
int ok = 1;
for (int i = 0; i < 10; i++)
{
if (v[i] > 1)
{
ok = 0;
break;
}
}
if (ok == 1)
{
return 1;
}
return 0;
}
int main()
{
int n;
cin >> n;
for(int i = 1; i <= n; i++)
{
clean();
int x;
cin >> x;
while(x != 0)
{
v[x % 10]++;
x /= 10;
}
int k = verifica();
if(k == 0)
{
cout << "NU";
break;
}
}
cout << "DA";
return 0;
}
