Răspuns :
[tex]\it \dfrac{8}{x+11}=\dfrac{2}{3} \Rightarrow x+11=\dfrac{8\cdot3}{2} \Rightarrow x+11=12|_{-11} \Rightarrow x=1 \in\mathbb{Z}_+[/tex]
[tex]\it \dfrac{8}{x+11}=\dfrac{2}{3} \Rightarrow x+11=\dfrac{8\cdot3}{2} \Rightarrow x+11=12|_{-11} \Rightarrow x=1 \in\mathbb{Z}_+[/tex]