Răspuns :
[tex] V_{paralelipiped} [/tex]=L*l*h=10*4*18= 720 [tex] dm^{2} [/tex]
[tex] V_{cub} [/tex]=[tex] l^{2} [/tex]=[tex] 1^{2} [/tex]=1 [tex] dm^{2} [/tex]
nr de cuburi ce incap in cutie = [tex] \frac{ V_{paralelipiped} }{ V_{cub} } [/tex]=[tex] \frac{720}{1} [/tex]=720 de cuburi
[tex] V_{cub} [/tex]=[tex] l^{2} [/tex]=[tex] 1^{2} [/tex]=1 [tex] dm^{2} [/tex]
nr de cuburi ce incap in cutie = [tex] \frac{ V_{paralelipiped} }{ V_{cub} } [/tex]=[tex] \frac{720}{1} [/tex]=720 de cuburi
Volumul paralelipiped : L*l*h
1.Transformam cm in dm
40 cm = 4 dm
V paralelipiped =10*4*18
=720 dm => 720 cuburi
V cub =l la puterea 3 ( scz ca am uitat sa scriu ) si dupa imparteai volumul parl la volum cub
1.Transformam cm in dm
40 cm = 4 dm
V paralelipiped =10*4*18
=720 dm => 720 cuburi
V cub =l la puterea 3 ( scz ca am uitat sa scriu ) si dupa imparteai volumul parl la volum cub