Răspuns :
[tex]\it [(-2)^3]^4:(-4)^5=(-2)^{12}:(-2^2)^5=2^{12}:(-2^{10})==-2^2=-4[/tex]
Răspuns: [tex]\color{red}\large \boxed{\bf-2^{2} ~~sau ~ -4}[/tex]
Explicație pas cu pas:
[tex]\large \bf [(-2)^{3}]^{4} :(-4)^{5}= (-2)^{3\cdot4} :(-2^{2})^{5}= (-2)^{12} :(-2^{2\cdot 5})=[/tex]
[tex]\large \bf 2^{12} :(-2^{10})= -2^{12-10}= \boxed{\bf-2^{2} ~~sau ~ -4}[/tex]
==pav38==