Răspuns :
Răspuns:
Notam cu x- suma initiala
I. In prima zi
[tex]\frac{1}{2}dinx= \frac{1}{2} *x=\frac{x}{2}[/tex]
II. In a doua zi
[tex]x-\frac{x}{2}=\frac{2x}{2}-\frac{x}{2}=\frac{x}{2}\\\frac{1}{3} din \frac{x}{2}=\frac{1}{3}*\frac{x}{2}=\frac{x}{6}[/tex]
III. In a treia zi
[tex]\frac{x}{2}-\frac{x}{6}=\frac{3x}{6}-\frac{x}{6}=\frac{2x}{6}\\\frac{1}{2}din\frac{2x}{6}=\frac{1}{2}*\frac{2x}{6}=\frac{2x}{12}=\frac{x}{6}[/tex]
IV. In a patra zi
[tex]\frac{2x}{6}-\frac{x}{6}=\frac{x}{6}\\\frac{1}{3}din\frac{x}{6}=\frac{1}{3}*\frac{x}{6}=\frac{x}{18}\\\frac{x}{6}-\frac{x}{18}=\frac{3x}{18}-\frac{x}{18}=\frac{2x}{18}\\\frac{2x}{18}=24 =>2x=18*24= 432 =>x= 216[/tex]
Explicație pas cu pas: