Răspuns:
d) (x-3)²-16=0
x²-6x+9-16=0
x²-6x-7=0
∆=b²-4ac
==> ∆=(-6)²-4•1•-7
==>∆=36+28
==>∆=64
x1,x2=-b±√∆/ 2a
x1= -b-√∆ 2a = 6-√64 /2•1 = 6-8/2 = -2/2 = -1
x2= -b+√∆/ 2a= 6+√64 /2•1 = 6+8/2= 14/2 =7
==> S={-1;7}
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