1)
c% = mdx100/ms
=> ms = mdx100/c% = 7,5x25/100 = 1,875 kg sare
2)
Cm = md/MxVs ; M.CuSO4 = 64+32+4x16 = 160 g/mol
=> md = CmxVsxM
= 1,2x0,25x160 = 48 g CuSO4
3)
Cm = md/MxVs ; M.CaCO3 = 40+12+3x16 = 100 g/mol
=> Vs = md/CmxM
= 300/1,5x100 = 2 L sol.
4)
c% = mdx100/ms
=> md = msxc%/100
= 3x20/100 = 0,6 kg