👤
Hristustelian
a fost răspuns

Impartiti numarul 288 in parti direct proportionale cu 7,11,18.

Răspuns :

Miky93
a+b+c=288
a,b,c,  dp cu 7,11,18

a/7=b/11=c/18=k
a=7k
b=11k
c=18k

7k+11k+18k=288
36k=288
k=8

a=56
b=88
c=144
Anagrigore14
a+b+c=288
a,b,c,  dp cu 7,11,18

a/7=b/11=c/18=k
a=7k
b=11k
c=18k

7k+11k+18k=288
36k=288
k=8

a=56
b=88
c=144

Alte intrebari