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Stie cineva?......... ​

Stie Cineva class=

Răspuns :

Matei

Punctul 1

Se aplica Legea lui Ohm pe tot circuitul.

[tex]\displaystyle{ I =\frac{E}{R + r} }[/tex]

[tex]\displaystyle{ I = \frac{ 12}{10+2} = \frac{12}{12} }[/tex]

I = 1 amper

Punctul 2

Se aplica Legea lui Ohm pe o portiune de circuit.

[tex]\displaystyle{ I = \frac{U}{R} \rightarrow U = I \cdot R }[/tex]

[tex]\displaystyle{ U = 1 \cdot 10 }[/tex]

U = 10 volti

Punctul 3

S = 4 mm² = [tex]\displaystyle{ 4 \cdot 10^{-6} }[/tex] m

[tex]\displaystyle{ R = \frac{\rho\cdot l}{S} }[/tex]

[tex]\displaystyle{ R = \frac{2 \cdot 10^{-7} \cdot 20}{4 \cdot 10^{-6} } = \frac{40 \cdot 10^{-7} }{4 \cdot 10^{-6} } }[/tex]

[tex]\displaystyle{ R = 10 \cdot 10^{-1} = 10\cdot \frac{1}{10} }[/tex]

R = 1 ohm

[tex]\displaystyle{ I = \frac{E}{R + r} }[/tex]

[tex]\displaystyle{ I = \frac{12}{1 + 2} = \frac{12}{3} }[/tex]

Noua intensitate = 4 amperi