Dau coroana pentru raspuns urgent cu rezolvare
10 .Rezolvati in R ecuatiile :
a) 3-4x = 6x+13
b) (x+1)·(x-1)-(x-4)²=-1
c) [tex]\frac{x}{2} -\frac{x-2}{6} = 1[/tex]
a) 3-4x=6x+13 -4x-6x=13-3 -10x=10 x=-1 b) (x+1)(x-1)-(x-4)^2=-1 x^2-x+x-1-(x2-2*x*4+16)=-1 ( se reduc) => 8x=-1+1+16 x=16/8=2 c) x/2-(x-2)/6=1 (6x-2x+4)/12=12/12=> 3x=12-3 x=9/3=3
