Răspuns:
(a, b)∈{(4;12);(6;6);(12;4) (2;-6);(-6;2)}
in Z*
(a, b)∈{(4;12);(6;6);(12;4)in N*
Explicație pas cu pas:a=b=6
sau
a=4, b=12
sau
a=12, b=4
1/6+1/6=2/6=1/3
1/4+1/12=(1/4)*(4/3) =1/3
C.E , ab ∈N*
(a+b)/ab=1/3
3(a+b)=ab
asau b div cu 3
3a+3b=ab
b(3-a)=-3a
b=3a/(a-3)
b= (3a-9+9)/(a-3)
b=3+9/(a-3)
in N*
a-3=1.....a= 4....b=12
a03=3....a=6 ....b=6
a-3=9....a=12 ...b=4
in Z se adauga
a03=-1...a=2....b=-6
a-3=-3...a=0 , nu convine/m nu are sens
a-3=-9...a=-6 b=2
