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Rezolvați in R ecuațiile din necunoscuta
a) 5x+2=3x-7
b)2(5x-4)=7(2x-3)
c)
25(x+23)+6=32(x-2)+11
d) (2x-3) (3x+4)=(x+7)(6x-8)+3

Pls help

Răspuns :

Beea2289
a) 5x+2=3x-7
5x-3x=-7-2
2x=-9
x=-9/2
b) 25(x+23)+6=32(x-2)+11
25x+575+6=32x-64+11
25x-32x=-64+11-575-6
-7x=-634 | *(-1)
7x=634
x=634/7
c) 2(5x-4)=7(2x-3)
10x-8=14x-21
10x-14x=-21+8
-4x=-13 |*(-1)
4x=13
x=13/4
d)(2x-3)(3x+4)=(x+7)(6x-8)+3
2x*3x+8x-9x-12=x*6x-8x+42x-56+3
6x^2-x-12=6x^2+34x-53
Reducem termenii asemenea, adica 6x^2
-x-34x=12-53
-35x=-41 |*(-1)
35x=41
x=41/35

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