15)tgB=AC/AB=6/6√3=1/√3⇒B=30gr C=60 gr AC=BC/2(teorema 30-60gr)⇒ BC=12cm 16)sinC=AB/BC=12/24=1/2⇒C=30gr b=60gr AC³=24³-12³=576-144=432=144*3 AC=12√3cm 17)T.Inaltimii⇒AD³=DB*DC 64=4*DC DC=16 cm BC=16+4=20 cm T catetei⇒AC³=CD*BC=4*20 =80 AC=√80=4√5cm si AC³=16*20=320 AC=8√5cm sinB+sinC=AC/BC+AB/BC=8√5/20+4√5/20=16√5/20=4√5/5