Δ ABC - dr => (T. Pitagora) [tex]AC^{2} = BC^{2} - AB^{2} [/tex]
[tex] AC^{2} = 10 ^{2} - 8^{2} [/tex]
[tex]AC = \sqrt{100- 64} [/tex]
[tex]AC = \sqrt{36} [/tex]
AC = 6 cm
AD = [tex] \frac{c1·c2}{ip} [/tex]
AD = [tex] \frac{8·6}{10} [/tex]
AD = [tex] \frac{24}{5} [/tex]
AD = 4,8 cm
AC² = CD · AC
6² = 10 · CD
36 = 10CD
CD = 3,6 cm
BD = BC - DC
BD = 10 - 3,6
BD = 6,4 cm
