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Lucirusu11
a fost răspuns

(1+3+5+7+...+2001+2003) - (2+4+6+8+...+2000+2002);

Cine ma ajuta?? ​

135720012003 246820002002Cine Ma Ajuta class=

Răspuns :

Robertiosa
(1+3+5+7+…+2001+2003)-2(1+2+3+4+..+1000+1001)=
S1=2003(2003+1)/2
=2003*2004/2
=2003*1002
= 2007006

S2=1001(1001+1)/2
=1001*1002/2
=1001*501
= 501501

2007006-2*501501=
2007006-1003002=1004004

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