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Stoicalucadaniel706
a fost răspuns

MA PUTETI AJUTA VA ROG MULT

AH=1, AI=127, ACa=40, AO=16, AMg=24:
MHI=AH + AI=1+127=128 u.a.m
MCA(OG)2=ACa+3×AO+2×AH=40+2×16+2×1=40+32+2=74 u.a.m
M H2O=
MMg(OH)2=
​

Răspuns :

Mihaiimbrisca

Răspuns:

MH2O=2×1+16=18 u.a.m

MMg(OH)2=24+2×1+2×16=58 u.a.m

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