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1+2+3+...+100=


2+4+6+...+100=

Vă rog,repede!

Răspuns :

 

[tex]\displaystyle\bf\\1+2+3+...+100=\frac{100\times(100+1)}{2}=50\times101=5050\\\\\\2+4+6+...+100=2(1+2+3+...+50)=2\times\frac{50(50+1)}{2}=50\times51=2550[/tex]

 

 

 

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