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Sa se afle trei numere impare consecutive care au suma 1701

Răspuns :

MaVe
a+b+c=1701
a+2=b
b+2=c
a+a+2+a+2+2=1701
3a+6=1701
3a=1701-6
3a=1695
a=1695/3
a=565
565+2=567
567+2=569
a=565
b=567
c=569
V: 565+567+569=1132+569=1701
ValyRemus
a+a+2+a+4=1701
3a+6=1701
3a=1701-6
3a=1695

a=1695/3
a=565

b=a+2 = 567

c=a+4=569

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