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Baragan66
a fost răspuns

Calculati :
[tex] \sqrt{2} \times ( \frac{ \sqrt{2} }{2} )^{n - 1} [/tex]
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Răspuns :

Albatran

Răspuns:

(1/√2)^n

Explicație pas cu pas:

√2*(1/√2)^n=√2/√2^(n-1)= (√2/√2)/√2^n=1/√2^n

Targoviste44

[tex]\it \sqrt2\cdot\Big(\dfrac{\sqrt2}{2}\Big)^{n-1}=\sqrt2\cdot\Big(\dfrac{\sqrt2}{2}\Big)^{n}\cdot\Big(\dfrac{\sqrt2}{2}\Big)^{-1}=\sqrt2\cdot\dfrac{2}{\sqrt2}\cdot\Big(\dfrac{\sqrt2}{2}\Big)^{n}=2\cdot\Big(\dfrac{\sqrt2}{2}\Big)^{n}[/tex]

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