Răspuns :
Fie ΔABC isoscel, cu AB=BC
AC= 8cm
P= AB+BC+AC= 22cm
22= 8+2AB
14= 2AB⇒ AB=BC= 7cm.
AC= 8cm
P= AB+BC+AC= 22cm
22= 8+2AB
14= 2AB⇒ AB=BC= 7cm.
Fie ΔABC isoscel, cu AB=BC
AC= 8cm
P= AB+BC+AC= 22cm
22= 8+2AB
14= 2AB⇒ AB=BC= 7cm
tot asa am gandit si eu :3
AC= 8cm
P= AB+BC+AC= 22cm
22= 8+2AB
14= 2AB⇒ AB=BC= 7cm
tot asa am gandit si eu :3