Răspuns:
5.
[tex] \sqrt{4 + 2 \sqrt{3} } - \sqrt{ \sqrt{9} } + 3 - 2 \sqrt{3 } = \\ \sqrt{(1 + 3) {}^{2} } - \sqrt{3} + 3 - 2 \sqrt{3} = \\ 1 + \sqrt{3} - \sqrt{3} + 3 - 2 \sqrt{3} = \\ 1 + 3 - 2 \sqrt{3} = \\ 4 - 2 \sqrt{3} [/tex]