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Rezolvati prin metoda substituției :

[tex] \left \{ {{ \frac{x-2}{7} - \frac{x-y}{4}+8 =x+6 } \atop {-3x + \frac{2y-3x}{2}= - (9-y) }} \right. [/tex]

Răspuns :

Renatemambouko
(x-2)/7-(x-y)/4+8=x+6
-3x+(2y-3x)/2=-(9-y)

(x-2)/7-(x-y)/4=x-2
-6x+2y-3x=-18+2y

(x-2)/7-(x-y)/4=x-2
-6x-3x=-18

(x-2)/7-(x-y)/4=x-2
-9x=-18
x=2
inlocuim in 1 ecuatie
(2-2)/7-(2-y)/4=2-2
-(2-y)/4=0
2-y=0
y=2


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