Răspuns:
a.x²+2x=0
x(x+2=0=>
x1=0
x+2=0
x= -2
S={-2,0}
b)2x²-8x=0
2x(x-4)=0
x1=0
x-4=0
x2=4
S={0,4}
c)-6x²+x=0
x(-6x+1)=0
x1=0
-6x²+x=0
x(-6x+1)=0
x1=0
-6x+1=0
-6x-1=0
-6x=1
x= -1/6
S(-1/6,0)
d)4x²-12x+9=0
(2x)²-2*2*3x+3²=0
(2x-3)²=0
2x-3=0
x1=x2=3/2
Explicație pas cu pas: