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![class=](https://ro-static.z-dn.net/files/dcc/e13ca9f9a5c8dc1ab92893231c4e40e7.jpg)
Răspuns:
a (2^/7+3^/7+4^/7)÷3=9^/7÷3=3^/7
b(2/3+5/3+11/3)÷3=18/3÷3=6÷3=2
c[(3^/3-1)+(5^/3+7)]÷2=(8^/3+6)÷2=4^/3+3
sper ca te-a ajuat