Calculati media geometrică a nr:
a=
[tex]2 \sqrt{3} \times 3 \sqrt{6} + \sqrt{32} - 3 \sqrt{50} + \sqrt{80} \div \sqrt{10} - 5 \sqrt{2} = [/tex]
b=
[tex]( \frac{7}{3 \sqrt{2} } + \frac{1}{ \sqrt{2} } - \frac{5}{2 \sqrt{2} } ) \div \frac{5}{24} = [/tex]

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