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Tonimititica
a fost răspuns

rezolvati ecuatiile:
a) 2(x+1)=8 , apartine Q
b) 3(x-2)= 2x+5, x apartine R
c) 5(2x-4)=3(4x+2), x apartine R
d) x-2(x+1)=2x, x apartine Z
e) 2t+3 (2t-1)=t+4 (t-2), t apartine R
f) -4(x+√2)- 3( x+√2) = -11+2√2, x apartine R
g) 0,5 (x-2)=3x-4 (x- unu supra doi ), x apartine R
h) 6y-2(2y+1)=2y-2, y apartine N
i) 3(z+4)=3z+10, z apartine R

Răspuns :

a) 2(x+1)=8=>2x+2=8=>2x=6=>x=3; b)3(x-2)=2x+5=>3x-6=2x+5=>3x-2x=5+6 =>x=11; c)5(2x-4)=3(5x+2)=>10x-20=15x+6 =>10x-15x=20+6=>-5x=26=>x=-26/5 d)x-2(x+1)=2x=>x-2x-2=2x=>x-2x-2x=2=>-3x=2=>x=-2/3 e)2t+3(2t-1)=t+4(t-2)=>2t+6t-3=t+4t-8=>8t-5t=3-8=>3t=-5=>t=-5/3

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