Răspuns:
✿ Salut! ✿
Să ne reamintim:
- Când vrem să adunăm / scădem două fracții, numitorul (numărul de jos) trebuie să fie la fel (numitor comun).
✯✯✯ Rezolvare: ✯✯✯
①
a) [tex]\dfrac{4}{15}+\dfrac{^{3)}2}{3}=\dfrac{4}{15}+\dfrac{10}{15}=\boxed{\dfrac{14}{15}}[/tex]
b) [tex]\dfrac{16}{93}+\dfrac{^{3)}6}{31}=\dfrac{16}{93}+\dfrac{18}{93}=\boxed{\dfrac{34}{93}}[/tex]
c) [tex]\dfrac{7}{32}+\dfrac{^{2)}1}{16}=\dfrac{7}{32}-\dfrac{2}{32}=\boxed{\dfrac{5}{32}}[/tex]
d) [tex]\dfrac{23}{42}-\dfrac{^{3)}5}{14}=\dfrac{23}{42}-\dfrac{15}{42}=\dfrac{\not8}{\not42}=\boxed{\dfrac{4}{21}}[/tex]
②
a) [tex]\dfrac{^{2)}5}{12}+\dfrac{5}{24}=\dfrac{10}{24}+\dfrac{5}{24}=\dfrac{\not15}{\not24}=\boxed{\dfrac{5}{8}}[/tex]
b) [tex]\dfrac{^{4)}26}{21}+\dfrac{^{6)}13}{14}=\dfrac{104}{84}+\dfrac{78}{84}=\dfrac{\not182}{\not84}=\boxed{\dfrac{13}{6}}[/tex]
c) [tex]\dfrac{^{4)}4}{15}+\dfrac{^{3)}3}{20}=\dfrac{16}{60}+\dfrac{9}{60}=\dfrac{25}{60}=\boxed{\dfrac{5}{12}}[/tex]
d) [tex]\dfrac{5}{24}+\dfrac{^{2)}1}{12}+\dfrac{^{3)}3}{8}=\dfrac{5}{24}+\dfrac{2}{24}+\dfrac{9}{24}=\dfrac{16}{24}=\boxed{\dfrac{2}{3}}[/tex]
e) [tex]\dfrac{^{2)}7}{30}-\dfrac{^{3)}3}{20}=\dfrac{14}{60}-\dfrac{9}{60}=\dfrac{\not5}{\not60}=\boxed{\dfrac{1}{12}}[/tex]
f) [tex]\dfrac{^{4)}8}{15}-\dfrac{^{3)}9}{20}=\dfrac{32}{60}-\dfrac{27}{60}=\dfrac{5}{60}=\boxed{\dfrac{1}{12}}[/tex]
g) [tex]\dfrac{^{35)}8}{21}-\dfrac{^{21)}4}{35}=\dfrac{280}{735}-\dfrac{84}{735}=\dfrac{196}{735}=\boxed{\dfrac{4}{15}}[/tex]
h) [tex]\dfrac{^{2)}7}{6}-\dfrac{^{3)}3}{4}-\dfrac{1}{12}=\dfrac{14}{12}-\dfrac{9}{12}-\dfrac{1}{12}=\dfrac{4}{12}=\boxed{\dfrac{1}{3}}[/tex]
