100% ........................... 540 g Al impur
98% ............................ m.p. = 529,2 g Al pur
529,2 g n moli
2Al + 3Cl2 --> 2AlCl3
2x27 3
=> n = 529,2x3/2x27 = 29,4 moli Cl2
n = nr.moli = m/M, M.Cl2 = 35,5x2 = 71 g/mol
=> m = nxM = 29,4x71 = 2087,4 g Cl2
