sa se verifice egalitatile
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a) 4+8=12 b) 1×2×4×8=8×8=64 c)3×1+1×5=3+5=8=2^3
d) 2×(10-6)^3 : (2×9-2×8)^5 =2× 4^3 : (18-16)^5 =
= 2× 2^6 : 2^5 = 2^(1+6-5) =2^2=4
e) 2×[ 3+4×(1+1+0)×(8-4)]= 2× (3+4×2×4) = 2×(3+32)= 2×35= 70
f) 10× ( 4+4×(27-3×3)= 10×(4+4×18)=10×(4+72)=760
g) [2^(5+3)]^3 : 2^(4×5) ×1 :2^4 =
=(2^8)^3 : 2^20 : 2^4 = 2^(24-20-4) =2^0=1
h) [5^(2+3+4)] ^2 : 5^15 - 11^14: 11^4 : 11^(7+0+1) =
= 5^(9×2) : 5^15 - 11^14 :11^4 :11^8=
=5^(18-15) - 11^(14-4-8)= 5^3 - 11^2 = 125-121=4