Amestec echimolecular=nr egal de moli
luam x moli metan si x moli etan
1mol metan......16g; 1mol etan........30g
xmoli..............16x g; x....................30x g
16x+30x=46x=9200 => x=200moli
1mol....2moli
CH4 + 2O2 -> CO2 + 2H2O
200.....y=400moli
1mol......3,5moli
C2H6 + 7/2 O2 -> 2CO2 + 3H2O
200........z=700moli
y+z=1100moli O2
vom calcula volumul in conditii standard (1atm si 25°C sau 1atm si 298K)
pV=nRT
V=1100*0,082*298=26879,6L=26,87m³ O2
