Răspuns :
nr. consecutive pare sunt: a, a+2, a+4, a+6, a+8
a+a+2+a+4+a+6+a+8=60
5a+20=60
5a=60-20
5a=40
a=40/5
a=8
deci nr.pare consecutive sunt:8,10,12,14,16
a+a+2+a+4+a+6+a+8=60
5a+20=60
5a=60-20
5a=40
a=40/5
a=8
deci nr.pare consecutive sunt:8,10,12,14,16