Răspuns :
x=?....y=?...................0,25moli
Fe + 2HCl -> FeCl2 + H2
56g....2*36,5g...........1mol
x=56*0,25=14g Fe
y=0,25*73=18,25g HCl (md)
c=md*100/ms => ms=md*100/c=18,25*100/36,5=50g solutie
ms=md+mapa => mapa=ms-md=50-18,25=31,75g apa
Fe + 2HCl -> FeCl2 + H2
56g....2*36,5g...........1mol
x=56*0,25=14g Fe
y=0,25*73=18,25g HCl (md)
c=md*100/ms => ms=md*100/c=18,25*100/36,5=50g solutie
ms=md+mapa => mapa=ms-md=50-18,25=31,75g apa