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[tex] \frac{x-1}{3} + \frac{2x-5}{2} \leq 1 \frac{1}{6} [/tex]

Răspuns :

[tex] \frac{^2^)x-1}{3} + \frac{^3^)2x-5}{2} \leq \frac{^1^)7}{6} ~~~|*6\\\\ 2(x-1)+3(2x-5) \leq 7\\\\ 2x-2+6x-15 \leq 7\\\\ 8x-17 \leq 7\\\\ 8x \leq 7+17\\\\ 8x \leq 24\\\\ x \leq \frac{24}{8} \\\\ \bold{x \leq 3} \\ x\{0,1,2,3\}[/tex]

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