Răspuns :
Deci trasam cele dopua diagonale
Fie tr. COB
ung .O=90 grade ==> sinB=CO supra BC ==>
ung. B=60 grade sin 60= radical3 supra 2
BC=12
==> co supra 12=radical 3 supra 2
2CO=12x Radical3
CO=6radical 3=> AC=12 radical 3
==> COS B=OB supra BC ==>
Cos 60=1 supra 2
==> OB supra 12 =1 supra 2
12=OBx2
OB=6 =>DB=12
A=D(1)xD(2) /2= 12 radical 3x12 /2=72 radical 3
Fie tr. COB
ung .O=90 grade ==> sinB=CO supra BC ==>
ung. B=60 grade sin 60= radical3 supra 2
BC=12
==> co supra 12=radical 3 supra 2
2CO=12x Radical3
CO=6radical 3=> AC=12 radical 3
==> COS B=OB supra BC ==>
Cos 60=1 supra 2
==> OB supra 12 =1 supra 2
12=OBx2
OB=6 =>DB=12
A=D(1)xD(2) /2= 12 radical 3x12 /2=72 radical 3