Răspuns :
[tex]h= \frac{ \sqrt{3} }{2} *l=\frac{ \sqrt{3} }{2}*4 \sqrt{3} =2*3=6
[/tex]
A=[tex] \frac{ \sqrt{3} }{4} * l^{2} = \frac{ \sqrt{3} }{4} *(4 \sqrt{3} )[/tex]²=12√3
A=[tex] \frac{ \sqrt{3} }{4} * l^{2} = \frac{ \sqrt{3} }{4} *(4 \sqrt{3} )[/tex]²=12√3
Fie Ad_|_BC TP
Fie tr. ADC => Ac^2=Ad^2+DC^2
ung. D=90 grade (4radical3)^=AD^+(2 radical 3)^2
48=AD^2+12
AD=6cm
A=Bx h/2
= 4 radical 3 x 6 /2
= 12 radical 3
Fie tr. ADC => Ac^2=Ad^2+DC^2
ung. D=90 grade (4radical3)^=AD^+(2 radical 3)^2
48=AD^2+12
AD=6cm
A=Bx h/2
= 4 radical 3 x 6 /2
= 12 radical 3