Răspuns:
Explicație pas cu pas:
a) [tex]5\frac{1}{4} + 6\frac{1}{10} = \frac{5*4+1}{4} + \frac{6*10+1}{10} = \frac{21}{4} + \frac{61}{10}[/tex]
Aducem la acelasi numitor comun
[tex]\frac{21*5}{4*5} + \frac{61*2}{10*2} = \frac{105}{20} + \frac{122}{20} = \frac{105+122}{20} = \frac{227}{20}[/tex]
b) [tex]6\frac{1}{4} + 5\frac{2}{3} + 1\frac{17}{24} = \frac{6*4+1}{4} + \frac{5*3+2}{3} + \frac{1*24+17}{24} = \frac{25}{4} + \frac{17}{3} + \frac{41}{24}[/tex]
Aducem la acelasi numitor comun
[tex]\frac{25*6}{4*6} + \frac{17*8}{3*8} + \frac{41}{24} = \frac{150}{24} + \frac{136}{24} + \frac{41}{24} = \frac{150136+41}{24} = \frac{327}{24}[/tex]
Simplificam prin 3
[tex]\frac{327:3}{24:3} = \frac{109}{8}[/tex]
