Răspuns:
Explicație pas cu pas:
1. a) [tex]5\sqrt{7}+3\sqrt{7} =8\sqrt{7}[/tex]
b) [tex]3\sqrt{7} -5\sqrt{7}=-2\sqrt{7}[/tex]
2. a)[tex]4\sqrt{6} *(-2\sqrt{3} )=-8\sqrt{18}=-8*2 \sqrt{3} =-16\sqrt{3}[/tex]
b)[tex]4\sqrt{6} :(-2\sqrt{3} )= [4: (-2)] *\sqrt{6:3} = -2\sqrt{2}[/tex]
3. [tex]\frac{6}{\sqrt{2} } = \frac{6\sqrt{2} }{2} =3\sqrt{2}[/tex]
[tex]\frac{10}{\sqrt{5} } =\frac{10\sqrt{5} }{5} =2\sqrt{5} \\2\sqrt{5}=\sqrt{2^{2}*5 } =\sqrt{4*5} =\sqrt{20}[/tex]
[tex]3\sqrt{2} =\sqrt{3^{2} *2} =\sqrt{18}[/tex]
[tex]\sqrt{18} <\sqrt{20}[/tex]
