Răspuns :
(4x²-10x+7)/(x+1)≥1
4x²-10x+7≥x+1
4x²-10x-x+7-1≥0
4x²-11x+6≥0
4x²-11x+6=0
Δ=121-96=25
x1=(11-5)/8=6/8=3/4
x2=(11+5)/8=16/8=2
x -α 3/4 2 +α
4x²-11x+6 +++++++0-----------0++++++++++
x∈(-α,3/4]u[2,+α)
4x²-10x+7≥x+1
4x²-10x-x+7-1≥0
4x²-11x+6≥0
4x²-11x+6=0
Δ=121-96=25
x1=(11-5)/8=6/8=3/4
x2=(11+5)/8=16/8=2
x -α 3/4 2 +α
4x²-11x+6 +++++++0-----------0++++++++++
x∈(-α,3/4]u[2,+α)
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