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stiind ca x supra y = 1,(3), determinati raportul x-y supra x+y​

Răspuns :

Dianageorgiana794

Răspuns:

x/y=1,(3)

x/y=(13-1)/9=12/9=4/3

x/y=4/3=>x=4y/3

[tex]\frac{x-y}{x+y} =\frac{\frac{4y}{3} -y}{\frac{4y}{3}+y}=\frac{4y-3y}{4y+3y} =\frac{y}{7y} =\frac{1}{7}[/tex]

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