Fie a,b,c, cele trei parti invers proportionale => 12 ·a=10·b=18·c=k=>
a=k/12 b=k/10 iar c=k/18
si a+b+c=301 =>k/12 +k/10 +k/18 =301(aducem la acelasi numitor)
cmmc(12,10,18)=180 =>
15 k +18 k+ 10 k=301 ·180=54180
43k=54180
k=1260
a=1260/12=105
b=1260/10=126
c=1260/18=70
