Sa se afle suma primilor sase termeni!
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Răspuns:
b6= b1 * q ^(n-1)
243= b1* 3^ (6-1)
243=b1* 3^5
243=b1 * 243 => b1=1
S6= b1 * ( q^6-1)/(q-1)
S6= 1 * ( 3^6 - 1) / (3-1)
S6= (729-1)/2
S6= 728/2
S6=364