Răspuns :
E(x)=(x+1)²+(x-1)²-(x-2)(x+2)
E(1) E(√2)
(x+1)²+(x-1)²-(x-2)(x+2)=x²+2x+1+x²-2x+1-x²-2x+2x+4=x²+6
E(1)=1²+6=7
E(√2)=(√2)²+6=2+6=8
E(1) E(√2)
(x+1)²+(x-1)²-(x-2)(x+2)=x²+2x+1+x²-2x+1-x²-2x+2x+4=x²+6
E(1)=1²+6=7
E(√2)=(√2)²+6=2+6=8