Răspuns :
M H2O=2+16=18
18g H2O.........2g H2
Xg...................6g H2
X=18*6/2=54g
18g H2O.........2g H2
Xg...................6g H2
X=18*6/2=54g
M (masa molara) H2O=2x(ori)1+16
=18 g / mol - 1
In 18g H2O....1 g H
In x g H2O.....6 g H
18 supra x egal cu 1 supra 6
x= 18 (ori) 6 supra 1
x= 108 g H2O
=18 g / mol - 1
In 18g H2O....1 g H
In x g H2O.....6 g H
18 supra x egal cu 1 supra 6
x= 18 (ori) 6 supra 1
x= 108 g H2O