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Golgojanmaria
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Cum se restrange [tex]2 x^{2} +x-6[/tex] ?

Răspuns :

Simonarusu
rezolvam ecuatia 2x²+x-6=0
Δ=1+48=49
x₁,₂=(-1+/-7)/4
x₁=(-1+7)/4=6/4=3/2
x₂=(-1-7)/4=(-8)/4=-2
 2x²+x-6=(x-x₁)(x-x₂)=(x-3/2)(x+2)=(2x-3)(x+2)
Albastruverde12
[tex]2 x^{2} +x-6= \\ = (2x^{2} -8)+(x+2)= \\ =2( x^{2} -4)+(x+2)= \\ =2(x+2)(x-2)+(x+2)= \\ =(x+2)[2(x-2)+1]= \\ =(x+2)(2x-4+1)= \\ =(x+2)(2x-3).[/tex]

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