15,(6)=15 [tex] \frac{6}{9} [/tex]=[tex] \frac{141}{9} [/tex]
[tex] \frac{x+y+z}{3} [/tex]=
[tex] \frac{141}{9} [/tex]
x+y+z=[tex] \frac{141}{3} [/tex]
x+y+z=47
1,(6)=1 [tex] \frac{6}{9} = \frac{15}{9} [/tex]= [tex] \frac{5}{3} [/tex]
0,8(3)=[tex] \frac{75}{90}= \frac{5}{6} [/tex]
x+ [tex] \frac{5}{3}+y-\frac{5}{6}+z -\frac{5}{6} [/tex]=x+y+z+[tex] \frac{5}{3} - \frac{10}{6} [/tex]=x+y+z+0=x+y+z
Ma=(x+y+z)/3=47/3=15,(6)
