Răspuns:
La 6 x,y apartile (0,1) , (0,2) , (0,3), (0,4) , (0,5), (0,6), (1,1) ,(1, 2), (1,3) (1,4) (1,5) (2,2), (2,3) ,(2,4) ,(3,3), (4,2), (5,1)
la 7 se da factor comun 3 si se simplifica cu 3 fractia, ramane x+y/12 echiunitara, deci x,y apartine (0, 12), (1,11) , (2, 10) (3, 9) (4, 8) (5, 7) (6, 6) (7 5) (8 4) (9 3) (10 2) (11, 1), (12, 0)
